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Windows application (process) start from C# code

2012/10/19 09:06
Run notepad application example
using System.Diagnostics; // REQUIRED
private string programStartupDir = "";
private string logFile = "";
...
private void Form1_Load(object sender, EventArgs e)
{
   programStartupDir = Directory.GetCurrentDirectory();
   programStartupDir += "\\";
   logFile = programStartupDir + "Application_Log.txt";
}
...
private void menuItemShowLogFile_Click(object sender, EventArgs e)
{
   Process showFile = new Process();
   showFile.StartInfo.FileName = "notepad.exe";
   showFile.StartInfo.Arguments = logFile;
   showFile.Start();
}